5x^2+60x-55=0

Solution for 5x^2+60x-55=0 equation:

5x^2+60x-55=0

a = 5; b = 60; c = -55;
Δ = b2-4ac
Δ = 602-4·5·(-55)
Δ = 4700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4700}=\sqrt{100*47}=\sqrt{100}*\sqrt{47}=10\sqrt{47}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-10\sqrt{47}}{2*5}=\frac{-60-10\sqrt{47}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+10\sqrt{47}}{2*5}=\frac{-60+10\sqrt{47}}{10}
$